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Objective Questions

Latest GATE Chemistry Exam Question (Objective Questions), MCQ in English

Subjects : Chemistry

Question Bank GATE Chemistry Exam (Only MCQ) - English
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Chemistry

Question 1Single Answer
The state of a quantum system is described by:
  1. A
    A classical wave function
  2. B
    A quantum wave function ψ
  3. C
    A probability distribution
  4. D
    An energy eigenvalue
Question 2Single Answer
An anharmonic oscillator differs from a harmonic oscillator by having:
  1. A
    Infinite well potential
  2. B
    Linear potential
  3. C
    Non-parabolic potential
  4. D
    Constant potential
Question 3Single Answer
The Hermite polynomials are orthogonal with respect to:
  1. A
    Sinusoidal weight function
  2. B
    Uniform weight function
  3. C
    Exponential weight function
  4. D
    Gaussian weight function
Question 4Single Answer
The first excited state wave function of a harmonic oscillator has:
  1. A
    Infinite nodes
  2. B
    Zero nodes
  3. C
    Two nodes
  4. D
    One node
Question 5Single Answer
The lowering operator applied to the ground state of a harmonic oscillator yields:
  1. A
    First excited state
  2. B
    Zero
  3. C
    Ground state
  4. D
    Negative energy state
Question 6Single Answer
An anharmonic oscillator differs from a harmonic oscillator by having:
  1. A
    Constant potential
  2. B
    Linear potential
  3. C
    Infinite well potential
  4. D
    Non-parabolic potential
Question 7Single Answer
The Hermite polynomials are orthogonal with respect to:
  1. A
    Sinusoidal weight function
  2. B
    Uniform weight function
  3. C
    Exponential weight function
  4. D
    Gaussian weight function
Question 8Single Answer
The first excited state wave function of a harmonic oscillator has:
  1. A
    Infinite nodes
  2. B
    Zero nodes
  3. C
    Two nodes
  4. D
    One node
Question 9Single Answer
The lowering operator applied to the ground state of a harmonic oscillator yields:
  1. A
    Negative energy state
  2. B
    First excited state
  3. C
    Ground state
  4. D
    Zero
Question 10Single Answer
The anharmonic oscillators energy levels are:
  1. A
    Linear in n
  2. B
    Equally spaced
  3. C
    Non qually spaced
  4. D
    Proportional to n
Question 11Single Answer
The raising operator for a harmonic oscillator:
  1. A
    Leaves n unchanged
  2. B
    Decreases n by 1
  3. C
    Increases n by 1
  4. D
    Sets n to 0
Question 12Single Answer
The high-resolution mass spectrometry provides:
  1. A
    Optical rotation
  2. B
    Approximate molecular mass
  3. C
    No mass
  4. D
    Exact molecular mass
Question 13Single Answer
The MS/MS technique provides:
  1. A
    Optical rotation
  2. B
    Molecular weight only
  3. C
    No information
  4. D
    Fragmentation patterns
Question 14Single Answer
The anharmonic oscillators energy levels are:
  1. A
    Equally spaced
  2. B
    Non qually spaced
  3. C
    Linear in n
  4. D
    Proportional to n
Question 15Single Answer
The raising operator for a harmonic oscillator:
  1. A
    Leaves n unchanged
  2. B
    Decreases n by 1
  3. C
    Increases n by 1
  4. D
    Sets n to 0
Question 16Single Answer
The high-resolution mass spectrometry provides:
  1. A
    Approximate molecular mass
  2. B
    Exact molecular mass
  3. C
    No mass
  4. D
    Optical rotation
Question 17Single Answer
The MS/MS technique provides:
  1. A
    No information
  2. B
    Molecular weight only
  3. C
    Fragmentation patterns
  4. D
    Optical rotation
Question 18Single Answer
The UV-Vis absorption of peptides detects:
  1. A
    Peptide bonds at 190–220 nm
  2. B
    Aliphatic chains
  3. C
    No absorption
  4. D
    Sugars
Question 19Single Answer
The C-H bending in IR spectroscopy appears at:
  1. A
    1350–1480 cm
  2. B
    1700 cm
  3. C
    3400 cm
  4. D
    No absorption
Question 20Single Answer
The LC-MS technique combines:
  1. A
    No combination
  2. B
    Gas chromatography
  3. C
    Liquid chromatography and mass spectrometry
  4. D
    IR spectroscopy
Question 21Single Answer
UV-Vis spectroscopy is used to detect:
  1. A
    Conjugation in alkaloids
  2. B
    Aliphatic compounds
  3. C
    No compounds
  4. D
    Ionic salts
Question 22Single Answer
The mass spectrometry fragmentation pattern provides:
  1. A
    Molecular weight only
  2. B
    Structural information
  3. C
    No information
  4. D
    Optical rotation
Question 23Single Answer
The UV-Vis absorption of conjugated dienes occurs at:
  1. A
    340 nm
  2. B
    200–250 nm
  3. C
    No absorption
  4. D
    1700 nm
Question 24Single Answer
The amide I band in IR spectroscopy appears at:
  1. A
    1650 cm
  2. B
    3400 cm
  3. C
    1200 cm
  4. D
    No absorption
Question 25Single Answer
The ¹³C NMR chemical shift of an aromatic carbon is:
  1. A
    160–200 ppm
  2. B
    0–50 ppm
  3. C
    No shift
  4. D
    110–150 ppm
Question 26Single Answer
The TOF-MS technique measures:
  1. A
    No measurement
  2. B
    Molecular weight only
  3. C
    Mass-to-charge ratio
  4. D
    Optical rotation
Question 27Single Answer
UV-Vis spectroscopy of nucleic acids detects:
  1. A
    Phosphates
  2. B
    Sugars
  3. C
    No bases
  4. D
    Purine and pyrimidine bases
Question 28Single Answer
The LC-MS technique combines:
  1. A
    Gas chromatography
  2. B
    Liquid chromatography and mass spectrometry
  3. C
    No combination
  4. D
    IR spectroscopy
Question 29Single Answer
The mass spectrometry fragmentation pattern provides:
  1. A
    Structural information
  2. B
    Molecular weight only
  3. C
    No information
  4. D
    Optical rotation
Question 30Single Answer
The UV-Vis absorption of conjugated dienes occurs at:
  1. A
    340 nm
  2. B
    200–250 nm
  3. C
    No absorption
  4. D
    1700 nm
Question 31Single Answer
The ¹³C NMR chemical shift of an aromatic carbon is:
  1. A
    0–50 ppm
  2. B
    110–150 ppm
  3. C
    No shift
  4. D
    160–200 ppm
Question 32Single Answer
The TOF-MS technique measures:
  1. A
    Optical rotation
  2. B
    Molecular weight only
  3. C
    No measurement
  4. D
    Mass-to-charge ratio
Question 33Single Answer
UV-Vis spectroscopy of nucleic acids detects:
  1. A
    Phosphates
  2. B
    Sugars
  3. C
    No bases
  4. D
    Purine and pyrimidine bases
Question 34Single Answer
The LC-MS technique combines:
  1. A
    Liquid chromatography and mass spectrometry
  2. B
    Gas chromatography
  3. C
    No combination
  4. D
    IR spectroscopy
Question 35Single Answer
The UV-Vis absorption of conjugated dienes occurs at:
  1. A
    1700 nm
  2. B
    340 nm
  3. C
    No absorption
  4. D
    200–250 nm
Question 36Single Answer
The ¹³C NMR chemical shift of an aromatic carbon is:
  1. A
    160–200 ppm
  2. B
    0–50 ppm
  3. C
    No shift
  4. D
    110–150 ppm
Question 37Single Answer
The TOF-MS technique measures:
  1. A
    No measurement
  2. B
    Molecular weight only
  3. C
    Mass-to-charge ratio
  4. D
    Optical rotation
Question 38Single Answer
UV-Vis spectroscopy of nucleic acids detects:
  1. A
    Purine and pyrimidine bases
  2. B
    Sugars
  3. C
    No bases
  4. D
    Phosphates
Question 39Single Answer
The CN stretch in IR spectroscopy appears at:
  1. A
    2200–2300 cm
  2. B
    1700 cm
  3. C
    3400 cm
  4. D
    No absorption
Question 40Single Answer
The ¹H NMR integration indicates:
  1. A
    Number of protons
  2. B
    Molecular weight
  3. C
    No information
  4. D
    Functional groups
Question 41Single Answer
The GC-MS technique is used for:
  1. A
    Volatile organic compounds
  2. B
    Proteins
  3. C
    No compounds
  4. D
    Sugars
Question 42Single Answer
The UV-Vis absorption of chlorophyll occurs at:
  1. A
    400–700 nm
  2. B
    200 nm
  3. C
    No absorption
  4. D
    1700 nm
Question 43Single Answer
The C=O stretch in esters appears at:
  1. A
    3400 cm
  2. B
    1700 cm
  3. C
    1730–1750 cm
  4. D
    No absorption
Question 44Single Answer
The molecular ion peak in mass spectrometry represents:
  1. A
    No ion
  2. B
    Fragment ion
  3. C
    Intact molecule
  4. D
    Radical ion
Question 45Single Answer
UV-Vis spectroscopy is used for:
  1. A
    No compounds
  2. B
    Aliphatic alkanes
  3. C
    Conjugated systems in carotenoids
  4. D
    Ionic salts
Question 46Single Answer
The C=C stretch in IR spectroscopy appears at:
  1. A
    1600–1680 cm
  2. B
    3200 cm
  3. C
    1700 cm
  4. D
    No absorption
Question 47
The ¹³C NMR chemical shift of a carbonyl carbon is:
  1. A
    160–200 ppm
  2. B
    0–50 ppm
  3. C
    No shift
  4. D
    5–
Question 48Single Answer
The ESI-MS technique is used for:
  1. A
    Biomolecules like proteins
  2. B
    Small volatile compounds
  3. C
    No compounds
  4. D
    Inorganic salts
Question 49Single Answer
The N-H stretch in IR spectroscopy appears at:
  1. A
    3300–3500 cm
  2. B
    1700 cm
  3. C
    1200 cm
  4. D
    No absorption
Question 50Single Answer
The ¹H NMR splitting pattern indicates:
  1. A
    Molecular weight
  2. B
    Number of neighboring protons
  3. C
    No information
  4. D
    Functional groups
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